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Proof step 4 from proof modby6-help (previous step)

⊦ (i + 1) * (2 + i) * (2 * (i + 1) + 1) = 6 * ((i + 1) * i + i + 1) + i * (i + 1) * (2 * i + 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ (i + i0) * j = i * j + i0 * j
Proof step 6:
⊦ (i + 1) * (2 + i) * (2 * (i + 1) + 1) = 6 * ((i * i + 1 * i) + i + 1) + i * (i + 1) * (2 * i + 1)

Rule argument

spec: int-mult inst: name: dist-lsplit seq: ⊦ (i + i0) * j = i * j + i0 * j subst: [j, i0, i] → [i, 1, i] flags: rewrite

Additional information

Used terms: i, 1, i