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Proof step 16 from proof modeq-neg-02 (previous step)

j * (i1 + i0) + j1 = i2 * j + j0, 0 < j1, 1 < j1, 0 < j + j0, j0 < 0, 0 ≤ i1 * j + j1, 0 < j, 1 < j, i0 < 0, j1 < j, j0 < j, j0 < j1, i2 * j + j0 < 0, j0 ≤ j1, j0 + j < j1, 2 * j + j0 < j, j0 + j < j, 2 * j + j0 ≤ j1 ⊦ j1 = j0 + j, j1 = 0, j0 = 0

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: 2 * j + j0 = (j0 + j) + j

Additional information

Used simplifier rules: add-mult-two: ⊦ i + i = 2 * i; from specification int-mult%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%add-in: ⊦ i + j = i + i0 ↔ j = i0; from specification int-basic2 Used formulas: 2 * j + j0 = (j0 + j) + j