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Proof step 2 from proof modex-odd-neg-01 (previous step)

⊦ i % 2 = ~1 ↔ (∃ j. i = 2 * j + 1 ∧ j < 0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i % 2 = ~1 ↔ (∃ j. i = 2 * j - 1 ∧ j ≤ 0)
Proof step 4:
⊦ (∃ j. i = 2 * j - 1 ∧ j ≤ 0) ↔ (∃ j. i = 2 * j + 1 ∧ j < 0)

Rule argument

spec: int-div inst: name: modex-odd-neg seq: ⊦ i % 2 = ~1 ↔ (∃ j. i = 2 * j - 1 ∧ j ≤ 0) subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i