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Proof step 5 from proof modex-odd-neg (previous step)

i < 0 ⊦ i % 2 = ~1 ↔ (∃ j. 2 * j = i + 1 ∧ j ≤ 0)

User applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
⊦ 0 < j ∧ i < 0 → (i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ j0 ≤ 0 ∧ abs(j0) < j ∧ i0 ≤ 0)
Proof step 7:
i = i0 * 2 + j0 ∧ j0 ≤ 0 ∧ abs(j0) < 2 ∧ i0 ≤ 0 ∧ 0 < 2, i < 0 ⊦ j0 = ~1 ↔ (∃ j. 2 * j = i + 1 ∧ j ≤ 0)

Rule argument

spec: int-div inst: name: div-elim-negpos seq: ⊦ 0 < j ∧ i < 0 → ( i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ j0 ≤ 0 ∧ abs(j0) < j ∧ i0 ≤ 0) subst: [i, j, i0, j0] → [i, 2, i0, j0] flags: rewrite, current

Additional information

Used terms: i, 2, i0, j0