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Proof step 19 from proof modmod-add-law-pos (previous step)

(i + i0) % j < j, (i + i0) % j = (i + i0 % j) % j + j, (i + i0) % j = (i0 % j + i % j) % j + 2 * j, 0 < j ⊦ j = 0

User applied rule insert equation

And obtained the following new goals

Proof step 20:
(i0 % j + i % j) % j + 2 * j < j, (i0 % j + i % j) % j + 2 * j = (i + i0 % j) % j + j, 0 < j ⊦ j = 0

Rule argument

pos: left 3 flags: discard

Additional information