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Proof step 1 from proof modmod-add-zero (conclusion)

0 < j ⊦ (i + i0 % j) % j = 0 → (i + i0) % j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
(i + i0 % j) % j = 0, 0 < j ⊦ (i + i0) % j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs