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Proof step 22 from proof modmod-add-zero (previous step)

i + i1 * j + j0 = i1 * j + i + j0, (i + j0) % j = 0, j0 < j, 0 < j, 0 ≤ j0, 0 ≤ i1 ⊦ (i + i1 * j + j0) % j = 0, 0 = j, 0 ≤ i, i ≤ 0 ∧ i1 * j + j0 ≤ 0

User applied rule insert equation

And obtained the following new goals

Proof step 23:
(i + j0) % j = 0, j0 < j, 0 < j, 0 ≤ j0, 0 ≤ i1 ⊦ (i1 * j + i + j0) % j = 0, 0 = j, 0 ≤ i, i ≤ 0 ∧ i1 * j + j0 ≤ 0

Rule argument

pos: left 1 flags: discard

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