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Proof step 4 from proof modmod-add-zero (previous step)

¬(0 < j ∧ 0 ≤ i0 ∧ 0 ≤ i), (i + i0 % j) % j = 0, 0 < j ⊦ (i + i0) % j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information