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Proof step 2 from proof modmod-ma (previous step)

0 ≤ i, 0 ≤ i0, 0 ≤ j0, 0 < j ⊦ (i % j * i0 % j + j0) % j = (i * i0 + j0) % j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
0 < j ⊦ 0 ≤ i ∧ 0 ≤ i0 → (i % j + i0) % j = (i + i0) % j
Proof step 4:
0 < j ∧ 0 ≤ i * i0 ∧ 0 ≤ j0, 0 ≤ i, 0 ≤ i0, 0 ≤ j0, 0 < j ⊦ (i % j * i0 % j + j0) % j = ((i * i0) % j + j0) % j

Rule argument

spec: int-div inst: name: modmod-add seq: 0 < j ⊦ 0 ≤ i ∧ 0 ≤ i0 → (i % j + i0) % j = (i + i0) % j subst: [j, i0, i] → [j, j0, i * i0] flags: rewrite, current

Additional information

Used simplifier rules: zero-ge-02: ⊦ 0 ≤ i → (0 ≤ i * j ↔ ¬ ¬(i = 0 ∨ 0 ≤ j)); from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult%zero-gels-04: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs Used terms: j, j0, i * i0