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Proof step 1 from proof modmod-mult-02 (conclusion)

0 < j ⊦ (i % j * i0 % j) % j = (i * i0) % j

User applied rule cut formula

And obtained the following new goals

Proof step 2:
i < 0, 0 < j ⊦ (i % j * i0 % j) % j = (i * i0) % j
Proof step 10:
0 < j ⊦ i < 0, (i % j * i0 % j) % j = (i * i0) % j

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0