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Proof step 2 from proof modmod-mult-05 (previous step)

j0 < 0 ⊦ j ≠ 0 ∧ j0 ≠ 0 → (i % (j * j0)) % j = i % j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j0 < 0 ⊦ (i % (j * j0)) % j = i % j, j0 = 0, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs