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Proof step 18 from proof modmod-mult-07 (previous step)

~(~ i % j) * i0 = ~ i % j * ~ i0, j ≠ 0 ∧ i < 0, i0 < j, i0 < 0, i + 1 < j, 0 < j, i < 0, i < j, i0 + 1 < j ⊦ (~(~ i % j) * i0) % j = (i * i0) % j, j = 0

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

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