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Proof step 23 from proof modmod-mult-07 (previous step)

(i % j * i0) % j = ~(i % j * ~ i0) % j, i0 < j, i0 < 0, 0 ≤ i, 0 < j, i0 + 1 < j ⊦ (i % j * i0) % j = (i * i0) % j

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information