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Proof step 6 from proof modmod-mult-07 (previous step)

i < j, i < 0, 0 < j, i + 1 < j ⊦ (i % j * i0) % j = (i * i0) % j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
j ≠ 0 ⊦ i < 0 → (* i) % j = ~(~ i % j)
Proof step 8:
j ≠ 0 ∧ i < 0, i < j, i < 0, 0 < j, i + 1 < j ⊦ (~(~ i % j) * i0) % j = (i * i0) % j

Rule argument

spec: int-div inst: name: modnum-neg seq: j ≠ 0 ⊦ i < 0 → (* i) % j = ~(~ i % j) subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%lf-02: ⊦ i < j ∧ j = i0 → i < i0; (forward) from specification int-basic1 Used terms: j, i