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Proof step 3 from proof mult-03 (previous step)

i * j - i0 = (i - 1) * j + (j - i0), i0 < j, 0 < i0, 0 < j, 1 < j, 0 < i, 0 < j0 ⊦ (i * j - i0) / (j0 * j) = (i - 1) / j0

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information