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Proof step 10 from proof mult-ls (previous step)

i / j < i0, i0 * j ≤ i, 0 < j, 0 ≤ i ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
⊦ 0 < j ∧ 0 ≤ i → (i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ 0 ≤ j0 ∧ j0 < j)
Proof step 12:
i = i1 * j + j0 ∧ 0 ≤ j0 ∧ j0 < j, i1 < i0, i0 * j ≤ i, 0 < j, 0 ≤ i ⊦

Rule argument

spec: int-div inst: name: div-elim-pos seq: ⊦ 0 < j ∧ 0 ≤ i → ( i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ 0 ≤ j0 ∧ j0 < j) subst: [i, j, i0, j0] → [i, j, i1, j0] flags: rewrite, current

Additional information

Used simplifier rules: zero-gels-04: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs Used terms: i, j, i1, j0