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Proof step 1 from proof neg-01 (conclusion)

j ≠ 0 ⊦ ~ i / j = ~(i / j)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Div-left: ⊦ j ≠ 0 → ~ i / j = ~(i / j);%neg-12: ⊦ ~ i = ~ j ↔ i = j; from specification int-abs