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Proof step 8 from proof nls-mult-div (previous step)

(i * i1) / j < i, 0 < j, i < (i * i1) / j, i1 < j, 1 < (i * i1) / j, 0 < (i * i1) / j, 0 < i ⊦ i = 0

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 9:
⊦ i < j ∧ j < j0 → i < j0
Proof step 10:
i < (i * i1) / j ∧ (i * i1) / j < i → i < i, (i * i1) / j < i, 0 < j, i < (i * i1) / j, i1 < j, 1 < (i * i1) / j, 0 < (i * i1) / j, 0 < i ⊦ i = 0

Rule argument

spec: int-basic1 inst: name: trans seq: ⊦ i < j ∧ j < j0 → i < j0 subst: [i, j, j0] → [i, (i * i1) / j, i] flags:

Additional information

Used terms: i, (i * i1) / j, i