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Proof step 2 from proof num-neg (previous step)

j ≠ 0 ⊦ i < 0 → i / j = ~(~ i / j)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Div-left: ⊦ j ≠ 0 → ~ i / j = ~(i / j);%neg-02: ⊦ ~ ~ i = i; from specification int-abs