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Proof step 2 from proof nummult-eq-01 (previous step)

j ≠ 0, j0 % j = 0 ⊦ i * j = i0 * j0 ↔ i = i0 * j0 / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j0 % j = 0, i * j = i0 * j0 ⊦ j = 0, i = i0 * j0 / j

Rule argument

Additional information

Used simplifier rules: mult-div-switch: ⊦ j ≠ 0 ∧ i % j = 0 → i / j * j = i;%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult