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Proof step 6 from proof nummult-le (previous step)

j0 < i, 0 < i, 0 ≤ j0, 0 ≤ i1 ⊦ i * i0 ≤ i1 * i + j0 ↔ i0 ≤ i1

User applied rule case distinction

And obtained the following new goals

Proof step 7:
i * i0 ≤ i1 * i + j0, j0 < i, 0 < i, 0 ≤ j0, 0 ≤ i1 ⊦ i0 ≤ i1
Proof step 10:
i0 ≤ i1, j0 < i, 0 < i, 0 ≤ j0, 0 ≤ i1 ⊦ i * i0 ≤ i1 * i + j0

Rule argument

pos: right 1

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