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Proof step 14 from proof nummult-ls-03 (previous step)

j + 1 = i2 * (i3 + 1) + j0, abs(j0) < i2, j < 0, i3 * i2 + j0 ≤ j, j0 ≤ 0, j0 < i2, 0 < i2, i3 * i2 + j0 < 0 ⊦ j < i2 * i0 ↔ i3 < i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ ¬ i < j ↔ j ≤ i
Proof step 16:
j + 1 = i2 * (i3 + 1) + j0, abs(j0) < i2, j < 0, i3 * i2 + j0 ≤ j, j0 ≤ 0, j0 < i2, 0 < i2, i3 * i2 + j0 < 0 ⊦ j < i2 * i0 ↔ ¬ i0 ≤ i3

Rule argument

spec: int-abs inst: name: lels seq: ⊦ ¬ i < j ↔ j ≤ i subst: [j, i] → [i0, i3] flags: rewrite

Additional information

Used terms: i0, i3