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Proof step 7 from proof nummult-ls-03 (previous step)

j < 0, i1 ≤ j, i1 < 0 ⊦ j < (j + 1 - i1) * i0 ↔ i1 / (j + 1 - i1) < i0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
j + 1 = i2 + i1, j < 0, i1 ≤ j, i1 < 0 ⊦ j < i2 * i0 ↔ i1 / i2 < i0

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j + 1, i1, i] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j + 1, i1, i