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Proof step 1 from proof nummult-ls (conclusion)
⊦ 0 < i ∧ 0 ≤ j → ((* i) * i0 < (* j) ↔ i0 < (i + j - 1) / i)
Special step normalize
And obtained the following new goals
Proof step 2
:
⊦ 0 < i ∧ 0 ≤ j → (i * i0 < j ↔ i0 < (i + j - 1) / i)