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Proof step 2 from proof nummult-modls-01 (previous step)

0 < j, j < i, i % j = 0 ⊦ i * i0 < j * j0 ↔ i / j * i0 < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i % j = 0, j < i, 0 < j, 0 < i, 1 < i ⊦ i * i0 < j * j0 ↔ i / j * i0 < j0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1