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Proof step 1 from proof one-02 (conclusion)

j ≠ 0 ⊦ 1 / j = 1 ↔ j = 1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-eq-same-01: j ≠ 0 ⊦ i / j = i ↔ i = 0 ∨ j = 1;