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Proof step 4 from proof one-neg (previous step)

1 / j < 0 ⊦ 0 < j ∧ 0 < 1, j = 0, j = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
1 / j < 0, j < 0 ⊦ j = 0, j = ~1

Rule argument

Additional information

Used simplifier rules: lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs