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Proof step 8 from proof one-neg (previous step)

1 = i0 * j + j0, i0 < j0, j < j0, 0 ≤ j0, j0 < abs(j), i0 < 0, i0 + 1 < abs(j), i0 < abs(j), j < 0 ⊦ j = 0, j = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ j < 0 → abs(j) = 0 - j
Proof step 10:
j < 0, 1 = i0 * j + j0, i0 < j0, j < j0, 0 ≤ j0, j0 < 0 - j, i0 < 0, i0 + 1 < 0 - j, i0 < 0 - j, j < 0 ⊦ j = 0, j = ~1

Rule argument

spec: int-abs inst: name: Abs-neg seq: ⊦ j < 0 → abs(j) = 0 - j subst: [j] → [j] flags: rewrite

Additional information

Used terms: j