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Proof step 3 from proof one (previous step)

⊦ 0 < 1 ∧ 0 ≤ i, i / 1 = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i < 0 ⊦ i / 1 = i

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs