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Proof step 1 from proof pos (conclusion)

⊦ 0 < j ∧ 0 ≤ i → 0 ≤ i / j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-zero-nls: ⊦ 0 ≤ i ∧ 0 < j → ¬ i / j < 0;%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs