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Proof step 3 from proof square-even-02 (
previous step
)
⊦ ((i + 1) * ((i + 1) + 1)) % 2 = 0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 4
:
⊦ (i * (i + 1)) % 2 = 0
Rule argument
spec: int-div inst: name: square-even-01 seq: ⊦ (i * (i + 1)) % 2 = 0 subst: [i] → [i + 1] flags: rewrite, current
Additional information
Used terms: i + 1