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Proof step 1 from proof zero-07 (conclusion)

j ≠ 0 ⊦ 0 < i → i / j ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < i / j, 0 < i, 0 < i / j, 1 < i / j ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs