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Proof step 11 from proof case-20 (previous step)

1 < i, 0 < i, 10 < i, i < 17 ⊦ i = 19, i = 18, i = 17, i = 16, i = 15, i = 14, i = 13, i = 12, i = 11, i = 10

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ i ≠ j -1 → (i < j ↔ i < j -1)
Proof step 13:
i ≠ 17 -1, 1 < i, 0 < i, 10 < i, i < 17 -1 ⊦ i = 19, i = 18, i = 17, i = 16, i = 15, i = 14, i = 13, i = 12, i = 11, i = 10

Rule argument

spec: int-basic1 inst: name: ls-rec seq: ⊦ i ≠ j -1 → (i < j ↔ i < j -1) subst: [j, i] → [17, i] flags: rewrite

Additional information

Used terms: 17, i