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Proof step 26 from proof case-20 (previous step)

1 < i, 0 < i, 10 < i, i < 12 ⊦ i = 19, i = 18, i = 17, i = 16, i = 15, i = 14, i = 13, i = 12, i = 11, i = 10

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
⊦ i ≠ j -1 → (i < j ↔ i < j -1)

Rule argument

spec: int-basic1 inst: name: ls-rec seq: ⊦ i ≠ j -1 → (i < j ↔ i < j -1) subst: [j, i] → [12, i] flags: rewrite

Additional information

Used simplifier rules: num-between: i + 1 = i0 ⊦ j < (* i0) → ¬ (* i) < j; from specification int-basic2 Used terms: 12, i