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Proof step 2 from proof case-40 (previous step)

1 < i, 0 < i, 30 < i, i < 40 ⊦ i = 39, i = 38, i = 37, i = 36, i = 35, i = 34, i = 33, i = 32, i = 31, i = 30

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i ≠ j -1 → (i < j ↔ i < j -1)
Proof step 4:
i ≠ 40 -1, 1 < i, 0 < i, 30 < i, i < 40 -1 ⊦ i = 39, i = 38, i = 37, i = 36, i = 35, i = 34, i = 33, i = 32, i = 31, i = 30

Rule argument

spec: int-basic1 inst: name: ls-rec seq: ⊦ i ≠ j -1 → (i < j ↔ i < j -1) subst: [j, i] → [40, i] flags: rewrite

Additional information

Used terms: 40, i