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Proof step 5 from proof coprime-mod-zero (previous step)

(i * i0) % j = 0, gcd(i, j) = 1, j | i * i0 → j | i0 ⊦ j = 0, i0 % j = 0

User applied rule case distinction

And obtained the following new goals

Proof step 6:
(i * i0) % j = 0, gcd(i, j) = 1 ⊦ j | i * i0, j = 0, i0 % j = 0
Proof step 8:
j | i0, (i * i0) % j = 0, gcd(i, j) = 1 ⊦ j = 0, i0 % j = 0

Rule argument

pos: left 3

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