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Proof step 6 from proof coprime-pot (previous step)

0 < j0, i * i0 = j ^ j0 -1 * j, gcd(i, j) = 1, 0 < i, 1 < i, 0 < j0, ∀ j1, i, i0, j. i→n(j1) < i→n(j0) → i * i0 = j ^ j1 ∧ gcd(i, j) = 1 ∧ 0 < i ∧ 1 < i ∧ 0 < j1 → j = 0 ⊦ j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
gcd(i, j) = 1, i * i0 = j ^ (j0 - 1) * j, 0 < i, 1 < i, 0 < j0, ∀ j1, i, i0, j. i→n(j1) < i→n(j0) → i * i0 = j ^ j1 ∧ gcd(i, j) = 1 ∧ 0 < i ∧ 1 < i ∧ 0 < j1 → j = 0 ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: sub-pred: ⊦ i -1 = i - 1; from specification int-abs