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Proof step 1 from proof div-eq-one (conclusion)

⊦ i | j ∧ i ≠ 0 → (j / i = 1 ↔ j = i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j / i = 1, i | j ⊦ i = 0, j = i

Rule argument

Additional information

Used simplifier rules: div-same: i ≠ 0 ⊦ i / i = 1; from specification int-div