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Proof step 4 from proof div-gcd-is-neg-01-01 (previous step)

i0 < 0 → i0 / gcd(i, i0) ≤ 0, i0 < 0, 0 ≤ i0 / gcd(i, i0) ⊦

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

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