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Proof step 6 from proof div-gcd-is-neg-01-01 (previous step)

i0 / gcd(i, i0) ≤ 0, i0 < 0, 0 ≤ i0 / gcd(i, i0) ⊦ i0 / gcd(i, i0) ≠ 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-gcd-neg-not-zero: ⊦ i0 < 0 → i0 / gcd(i, i0) ≠ 0;