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Proof step 2 from proof div-gcd-not-neg (previous step)

i / gcd(i, i0) ≤ 0, i / gcd(i, i0) < i, 0 < i ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ gcd(i, j)
Proof step 4:
0 ≤ gcd(i, i0), i / gcd(i, i0) ≤ 0, i / gcd(i, i0) < i, 0 < i ⊦

Rule argument

spec: int-gcd inst: name: gcd-pos seq: ⊦ 0 ≤ gcd(i, j) subst: [i, j] → [i, i0] flags: current, []

Additional information

Used terms: i, i0