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Proof step 3 from proof div-gcd-zero (previous step)

gcd(i, i0) ≤ abs(i), i / gcd(i, i0) = 0 ⊦ i = 0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
gcd(i, i0) ≤ abs(i), i / gcd(i, i0) = 0 ⊦ i0 = 0, i = 0

Rule argument

fma: i0 = 0

Additional information

Used simplifier rules: gcd-zero-03: ⊦ i ≠ 0 → gcd(i, 0) = abs(i);%div-abs: ⊦ i ≠ 0 → i / abs(i) ≠ 0; from specification int-div Used formulas: i0 = 0