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Proof step 5 from proof div-mod (previous step)

¬(0 < j ∧ 0 ≤ i0 ∧ i0 ≤ i) ⊦ 0 < j ∧ 0 ≤ i ∧ 0 ≤ i0 → (j | ~(i0 - i) ↔ i % j = i0 % j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i | ~ j ↔ i | j
Proof step 7:
¬ 0 < j ∨ ¬ 0 ≤ i0 ∨ ¬ i0 ≤ i ⊦ 0 < j ∧ 0 ≤ i ∧ 0 ≤ i0 → (j | i0 - i ↔ i % j = i0 % j)

Rule argument

spec: int-gcd inst: name: div-neg seq: ⊦ i | ~ j ↔ i | j subst: [j, i] → [i0 - i, j] flags: rewrite, current

Additional information

Used terms: i0 - i, j