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Proof step 4 from proof divides-mod (previous step)

⊦ (∃ i0. i * i0 = j) ↔ j % i = 0, i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
j ≠ 0 ⊦ i % j = 0 ↔ (∃ j0. i = j0 * j)

Rule argument

spec: int-div inst: name: modex seq: j ≠ 0 ⊦ i % j = 0 ↔ (∃ j0. i = j0 * j) subst: [j, i] → [i, j] flags: rewrite

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: i, j