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Proof step 4 from proof divides-mult-02 (
previous step
)
i | j, ∃ i1. i0 * i1 = j0 ⊦ i * i0 | j * j0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
i | j ⊦ i * i0 | j * i0 * i1
Rule argument
Additional information