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Proof step 1 from proof divides-mult-add (conclusion)

⊦ i | i * j + j0 ↔ i | j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: divides-add: ⊦ i | j → (i | j + j0 ↔ i | j0);%div-mult: ⊦ i | i * j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult