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Proof step 2 from proof divides-mult-sub (
previous step
)
i * j - j0 = i * j + ~ j0 ⊦ i | i * j - j0 ↔ i | j0
User applied rule insert equation
And obtained the following new goals
Proof step 3
:
⊦ i | i * j + ~ j0 ↔ i | j0
Rule argument
pos: left 1 flags: discard
Additional information