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Proof step 3 from proof divides-pot-prime (previous step)

prime(i) ∧ 0 < j0, ∀ j1, i, j. i→n(j1) < i→n(j0) → prime(i) ∧ 0 < j1 → (i | j ^ j1 ↔ i | j) ∨ j = 0 ⊦ (i | j ^ j0 ↔ i | j) ∨ j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information