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Proof step 7 from proof divides-pot-prime (previous step)

prime(i), 0 < j0, i | j ^ (j0 - 1), ∀ j1, i, j. i→n(j1) < i→n(j0) → prime(i) ∧ 0 < j1 → (i | j ^ j1 ↔ i | j) ∨ j = 0 ⊦ j = 0, i | j

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
j0 = i0 + 1, prime(i), 0 < j0, i | j ^ i0, ∀ j1, i, j. i→n(j1) < i→n(j0) → prime(i) ∧ 0 < j1 → (i | j ^ j1 ↔ i | j) ∨ j = 0 ⊦ j = 0, i | j

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j0, 1, i0] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j0, 1, i0