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Proof step 19 from proof gcd-com (previous step)

gcd(j, i) < gcd(i, j) ⊦ gcd(i, j) | i ∧ (j ≠ 0 ∨ i ≠ 0)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-gcd inst: name: gcd-div1 seq: ⊦ gcd(i, j) | i subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used simplifier rules: gcd-zero: ⊦ gcd(0, 0) = 0; Used terms: j, i